com.lowagie.text.html
Class WebColors

java.lang.Object
  java.util.AbstractMap<K,V>
      java.util.HashMap
          com.lowagie.text.html.WebColors

All Implemented Interfaces:

java.io.Serializable, java.lang.Cloneable, java.util.Map

public class WebColors
extends java.util.HashMap

This class is a HashMap that contains the names of colors as a key and the corresponding Color as value. (Source: Wikipedia http://en.wikipedia.org/wiki/Web_colors )

Author:

blowagie

See Also:

Serialized Form

Nested Class Summary

Nested classes/interfaces inherited from class java.util.AbstractMap

java.util.AbstractMap.SimpleEntry<K,V>, java.util.AbstractMap.SimpleImmutableEntry<K,V>

Field Summary

static WebColors	NAMES HashMap containing all the names and corresponding color values.
private static long	serialVersionUID

Constructor Summary

WebColors()

Method Summary

static java.awt.Color

getRGBColor(java.lang.String name) Gives you a Color based on a name.

Methods inherited from class java.util.HashMap

clear, clone, containsKey, containsValue, entrySet, get, isEmpty, keySet, put, putAll, remove, size, values

Methods inherited from class java.util.AbstractMap

equals, hashCode, toString

Methods inherited from class java.lang.Object

finalize, getClass, notify, notifyAll, wait, wait, wait

Methods inherited from interface java.util.Map

equals, hashCode

Field Detail

serialVersionUID

private static final long serialVersionUID

See Also:

Constant Field Values

NAMES

public static final WebColors NAMES

HashMap containing all the names and corresponding color values.

Constructor Detail

WebColors

public WebColors()

Method Detail

getRGBColor

public static java.awt.Color getRGBColor(java.lang.String name)
                                  throws java.lang.IllegalArgumentException

Gives you a Color based on a name.

Parameters:

name - a name such as black, violet, cornflowerblue or #RGB or #RRGGBB or rgb(R,G,B)

Returns:

the corresponding Color object

Throws:

java.lang.IllegalArgumentException - if the String isn't a know representation of a color.